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| ?Re: accessing array using address variables |
Author:??(---.capfed2.sinectis.com.ar)
Date:???10-24-03 22:28
$int0="January";
$int1="February";
$int2="March";
$array1=array();
$ins="int";
$ins1="";
$ins2="";
$i=0;
for ($i=0;$i<3;$i++){
$ins1="int" . $i;
$ins2 = $ins1;
// notice the double dollar ($$)
$array1[$i]=$$ins1;
print("$ins2");
}
?>
this is easier than explaining
$age=21;
$var_name="age";
echo $$var_name; // returns 21
echo ${"ag" . "e"}; // the same as above
but for this case its better like this:
$months = array(null, "Jan", "Feb", ..., "Dec");
// january is not month zero!
echo $months[5]; // returns "May"
or even easier:
echo date("F", mktime(0, 0, 0, 12, 0, 0)); // returns "December"
see php.net
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| ?Topics |
Author? |
Date |
 
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?accessing array using address variables??new
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jan |
10-14-03 21:26? |
 
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?Re: accessing array using address variables??new
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federico |
10-24-03 22:28? |
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